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Step2247 [10]
3 years ago
10

1. Evaluate a/b + c^2d for a = 6,b=3,c=4,and d=5

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0

Answer:

1) C

2) A

3) D

Step-by-step explanation:

A) We substitute the values for a ,b , c and d in the given equation.\frac{6}{3} +4^2 (5) \\= 2+80\\=82

Hence option c. 82 is the answer.

2) The product 6(-3)

Since positive x negative gives negative

we get -(6x3) = -18

Option A is the answer.

3) For this we have to find cube of a fraction with numerator 4 and denominator 7

We find cube of numerator first = 4x4x4 =64

Cube of denominator = 7x7x7 = 343

Hence cube of fraction = 64/343

Option D

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In Question 1, what do you notice about the x-coordinates before and after a horizontal stretch? What do you notice about the y-
ozzi

Answer:

The value of nx is the ratio of the transformed x-coordinates to the original x-coordinates in each horizontal stretch. The value of ny is the ratio of the transformed y-coordinates to the original y-coordinates in each vertical stretch.

Step-by-step explanation:

PLATO

Mark me Brainliest plz, just a click of a button :)

6 0
3 years ago
Read 2 more answers
What shape is always created in graphing the addition of two vectors?
Gennadij [26K]
<h3>Answer: Parallelogram</h3>

You could use the parallelogram rule to add the vectors, or you could use the tip-to-tail method (your textbook might call it the "head to tail method" but it's the same idea).

An example of the parallelogram method is shown below with adding the vector u = (-4,4) in red to the vector v = (8,2) in blue to get the vector w = (4,6) in green. The green resultant vector is one of the diagonals of the parallelogram

Side note: The other diagonal is either u-v or v-u depending on your reference point.

3 0
3 years ago
Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability
krok68 [10]

Answer:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

So for this case we can solve for P(A) like this:

P(A) = 1-P(A') = 1-\frac{68}{73}=\frac{5}{73}

And now we can find P(A \cup B) using the total probability rul given by:

P(A \cup B) = P(A)+P(B) -P(A \cap B)

And if we replace the values given we got:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

And that would be the final answer.

5 0
3 years ago
There are two red jars of marbles and one blue jar of marbles jars of a certain color have the same number of marbles in them. T
satela [25.4K]
We can set up an equation to solve this problem.  I am setting the number of marbles in a red jar to R.

R + R + R - 16 = 41

We solve this by adding 16 to both sides and combining all of the R terms..  This gives us:

3R = 57

We can finish this problem by dividing both sides by 3.

R = 19.  So, there are 19 marbles in a red jar.

We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles.  I am setting the amount of marbles in a blue jar to B.

41 - 19*2 = B

B = 3

So, there are 3 marbles in a blue jar and 19 marbles in a red jar.



7 0
3 years ago
Write a recursive formula for an, the nth term of the sequence 3, -4, -11
yKpoI14uk [10]

Answer:

, 12, 48, 192...

a. Write a recursive formula for the nth term of the sequence

Ans: a(n+1) = 4*a(n)

------------------------------

b. Write a general formula for the nth term of the sequence

a(n) = 3*4^(n-1)

--------------

c. Calculate S10 for this sequence

Geometric sequence with a(1) = 3 and r = 4

----?

Step-by-step explanation:

8 0
2 years ago
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