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dangina [55]
4 years ago
8

If AC=3x, AB=15, and BC=2x-1, how could we solve for x?

Mathematics
1 answer:
irinina [24]4 years ago
5 0

Answer:

A. 3x = 15

or, x = 15/3

or, x = 5

B. 3x = 2x-1

or, 3x-2x = -1

or, x = -1

C. 3x+15 = 2x-1

or, 3x-2x = -1-15

or, x = -16

D. 3x = 15+(2x-1)

or, 3x = 15+ 2x-1

or, 3x-2x = 14

or, x = 14

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