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eimsori [14]
3 years ago
10

he table shows the cost of downloading songs. Number of Songs Cost 0 0 1 $1.25 2 $2.50 3 $3.75 4 $5.00 What does the rate of cha

nge mean in this situation? The cost increases $5.00 for each additional song that is downloaded. The cost increases $0.25 for each additional song that is downloaded. The cost increases $1.25 for each additional song that is downloaded. The cost increases $2.50 for each additional song that is downloaded.
Mathematics
2 answers:
Jet001 [13]3 years ago
5 0

Answer: C)The cost increases $1.25 for each additional song that is downloaded.

I took the test and got it right!


horsena [70]3 years ago
3 0
From the table we can see:
Number of songs:         Cost:
          0                         $ 0
          1                         $1.25
          2                         $2.50
          3                         $3.75
          4                         $5.00
Therefore the rate of change is: (2.50 - 1.25) / ( 2 - 1 ) = $1.25
Answer:
It means that : C. The cost increases $1.25 for each additional song that is downloaded.

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Which of the following statements best describes an angle that is in standard​ position? A. An angle is in standard position if
lorasvet [3.4K]

Answer: D. an angle is in standard position if the vertex is at the origin of a rectangular coordinate system and the initial side lies along the positive x-axis.




8 0
3 years ago
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Contact [7]

Answer:

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8 0
2 years ago
Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

6 0
3 years ago
Correct Answers only please!
Tcecarenko [31]

Answer:

C. $97

Step-by-step explanation:

The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.

average wage for 15 days = (sum of wages for the 15 days)/15

The amount of wages during a number of days is the product of the average wage of those days and the number of days.

First 7 days:

average wage: $87

number of days: 7

total wages in first 7 days = 7 * $87/day = $609

Last 7 days:

average wage: $92

number of days: 7

total wages in last 7 days = 7 * $92/day = $644

8th day:

wages of the 8th day is unknown, so we let x = wages of the 8th day

total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)

total wages of 15 days = 609 + x + 644 = x + 1253

average wage for 15 days = (sum of wages for the 15 days)/15

average wage for 15 days = (x + 1253)/15

We are told the average for the 15 days is $90/day.

(x + 1253)/15 = 90

Multiply both sides by 15.

x + 1253 = 1350

Subtract 1253 from both sides.

x = 97

Answer: $97

3 0
3 years ago
Pls help plssss I beg plsss
Daniel [21]

Answer:

2 1/4

so last option :)

4 0
3 years ago
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