3 years ago

How many ways can a person with five nickels, three dimes, and two quarters make a 75-cent purchase from the machine?

1 answer:

DIA [1.3K]3 years ago

8 0

2 quarters, 2 dimes, and 1 nickel

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Rudik [331]

Answer:

C = (A*P - 8.4Y -330T + 200I) / 100

Step-by-step explanation:

P = (8.4Y + 330T + 100C -200I ) / A

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A*P = 8.4Y + 330T -200I +100C

100C = A*P - 8.4Y - 330T + 200I

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4 years ago

How many ways can a person with five ​nickels, three​ dimes, and two quarters make a 75-cent purchase from the​ machine?