3 years ago

How many ways can a person with five nickels, three dimes, and two quarters make a 75-cent purchase from the machine?

Mathematics

1 answer:

DIA [1.3K]3 years ago

8 0

2 quarters, 2 dimes, and 1 nickel

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What is the missing numerator of 4/9= ?/81

yKpoI14uk [10]

To solve this question, first cross multiply
Let ? = x

4/9 = x/81

4(81) = 9(x)

Simplify.

81 x 4 = 324

324 = 9x

Isolate the x, divide 9 from both sides

324/9 = 9x/9

x = 324/9

x = 36

4/9 = 36/81

36 is your answer

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How many ways can a person with five ​nickels, three​ dimes, and two quarters make a 75-cent purchase from the​ machine?

How many ways can a person with five nickels, three dimes, and two quarters make a 75-cent purchase from the machine?