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k0ka [10]
3 years ago
14

Solving by elimination

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

x = 3

y = 6

Step-by-step explanation:

(-4x - y = -18)

2 (2x + 3y = 24)

-4x - y = -18

4x + 6y = 48

5 / 5y = 30 / 5

y = 6

______________________

-4x - (6) = -18

-4x - 6 + 6 = -18 + 6

-4x = -12

-4x / 4 = -12 / 4

x = 3

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Ymorist [56]
Ummm hmm this is a hard one..... I believe it’s 88?
7 0
3 years ago
A student wants to check six websites. Four of the websites are social and two are school-related. After checking just two sites
mash [69]

The approximate probability that she checked a social website first, then a school-related website is 0.267.

First step is to calculate the Total number of websites

Total number of websites=Number of school websites+Number of social websites

Total number of websites=2+4

Total number of websites=6

Second step

Probability of checking the social website first

Probability of checking social website=Number of social websites/Total number of websites

Probability of checking social website= 4/6

Third step

Since one social website is checked which means that she is left with 3 social website and 2 school websites

Total number websites=2+3

Total number websites=5

Forth step

Probability of checking social website=Number of school websites/Total number websites

Probability of checking social website=2/5

Fifth step

Probability= 4/6 x 2/5 = 0.2666

Probability=0.267(Approximately)

Inconclusion the approximate probability that she checked a social website first, then a school-related website is 0.267.

Learn more about probability here:brainly.com/question/25688842

6 0
3 years ago
Calculate the distance between the points (-6, 4) and (5, -1). Round to the nearest tenth.
ludmilkaskok [199]
It will be 42 because of the with times the 2nd highest
4 0
3 years ago
Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
We test for the origin because, it is not passing through the origin.

0 \geqslant - (0) + 2
This yields
0 \geqslant 2
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph
8 0
4 years ago
How do I find the inverse of this problem?
raketka [301]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Inverse of real function.

Let's consider here, g(n) = y ,

so we get as,

y =  \sqrt[3]{ \frac{n - 1}{2} }

no, cubing the power both side we get as,

=>

{y}^{3}  =  \frac{n - 1}{2}

now,

2 {y}^{3}  = n - 1

so finally, we get as,

=>

n = 2 {y}^{3}  + 1

hence,here, n = inverse of the g(n) function.

so,

g^-1 (n) = 2y^3+1.

7 0
3 years ago
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