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Ray Of Light [21]
1 year ago
14

I need help bad I dont understand this

Mathematics
1 answer:
Finger [1]1 year ago
4 0

Answer:

12.566 inches

Step-by-step explanation:

2πr/4

2π x8 divided by 4

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A certain college graduate borrows $5900 to buy a car. The lender charges interest at an annual rate of 10%. Assuming that inter
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This is the answer to your question

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2 years ago
Write the following inequality in slope-intercept form. 5x – 5y ≥ 70
White raven [17]
5x - 5y >= 70
Move the 5x to the right by subtracting 5x from both sides
- 5y >= -5x + 70
Divide both sides by -5 and when you divide by a negative you have to change the inequality sign.
y <= x - 14 Letter B
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3 years ago
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<img src="https://tex.z-dn.net/?f=7x%5E%7B3%7D%20%2A%207x%5E%7B5%7D%2A7x%5E%7B2%7D" id="TexFormula1" title="7x^{3} * 7x^{5}*7x^{
Natasha_Volkova [10]

{7x}^{3} . \:  {7x}^{5} . {7x}^{2} \\ 343 {x}^{3}   {x}^{5}  {x}^{2}  \\ 343 {x}^{10}  \\

4 0
2 years ago
Read 2 more answers
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
15.12 is what percent of 12?
Llana [10]

Answer:

<h2>126%</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\\begin{array}{ccc}15.12&-&p\%\\\\12&-&100\%\end{array}\qquad\text{cross multiply}\\\\\\12p=(15.12)(100)\\12p=1512\qquad\text{divide both sides by 12}\\p=126

\bold{METHOD\ 2}\\\\p\%=\dfrac{p}{100}\\\\p\%\ of\ 12\ is\ equal\ to\ 15.12:\\\\\dfrac{p}{100}\cdot12=15.12\\\\\dfrac{12p}{100}=15.12\qquad\text{multiply both sides by 100}\\\\12p=1512\qquad\text{divide both sides by 12}\\\\p=126

6 0
3 years ago
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