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Svetach [21]
2 years ago
11

Proper and improper fractions with shaded in

Mathematics
1 answer:
ohaa [14]2 years ago
5 0

Answer:

Where’s the rest of the question?

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1/5,0.4,1/2,0.7 on a number line
hoa [83]
Your going to have to draw it out,but just look for the number on your number line and put a point above the number.
8 0
2 years ago
-36 ÷ 4 A) 4 groups of 9 negatives B) 4 groups of 9 positives C) 9 groups of 4 negatives D) 9 groups of 4 positives
Valentin [98]

Answer:

A) 4 groups of 9 negatives

Step-by-step explanation:

-36/4

-9

This means we have 4 groups of 9 negatives

7 0
3 years ago
Write an equation for the line below.
Dmitry_Shevchenko [17]

Answer:

  x = 3

Step-by-step explanation:

A vertical line has the form x = constant. The graph shows the constant you want is 3.

4 0
2 years ago
A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec
Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

CI=\bar x\pm z_{\alpha/2}\times SE

For 5% level of significance the two tailed critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct the 95% confidence interval as follows:

CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0
2 years ago
Read 2 more answers
−3(3x−4)=2x+23 <br><br> helppppppppp
Assoli18 [71]

Answer:

The correct answer is -1

4 0
3 years ago
Read 2 more answers
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