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balu736 [363]
3 years ago
13

Guess a number for x that would make the equation true. Check your solution. 5x – 2 = 8

Mathematics
2 answers:
notka56 [123]3 years ago
5 0

Answer:

x=2

Step-by-step explanation:

5x-2 =8

Let x =2

5(2) -2 =8

10 -2 =8

8=8

The guess is true

Illusion [34]3 years ago
3 0

Answer:2

Step-by-step explanation:

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What is 8/15÷2/5?What so u think is the best answer for this problem??
Mademuasel [1]

Answer:

1 1/3

Step-by-step explanation:

Solve. Change the division sign into a multiplication, and flip the second fraction:

(8/15)/(2/5) = (8/15) x (5/2)

Multiply across:

(8 x 5)/(15 x 2) = (40)/(30)

Simplify. Divide common factors:

(40/30)/(10/10) = 4/3

4/3 or 1 1/3 is your answer.

~

5 0
3 years ago
Read 2 more answers
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7 0
3 years ago
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



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3 years ago
Find the missing angle. Find x
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Answer: 20

Reason: They're opposite meaning they are the same when compared to the side
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there are 27 red or blue marbles in a bag. The number of red marbles is 5 less than 3 times the number of blue marbles. How many
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