Answer:
The area of the remaining board is [(L × B) - (l × b)].
Step-by-step explanation:
Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.
Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.
The area of any rectangle is:
Area = Length × Breadth
The area of the bigger rectangle is:
Area of ABCD = L × B
The area of the smaller rectangle is:
Area of PQRS = l × b
Then the area of the remaining board will be:
Area of remaining board = Area of ABCD - Area of PQRS
= (L × B) - (l × b)
Thus, the area of the remaining board is [(L × B) - (l × b)].
Answer:
-5x+4
Step-by-step explanation:
(3x*2x-6x+2)-(4x*2x-3x-2)
(3*2x-6x+2)-(4*2x-3x-2)
(6x-6x+2)-(8x-3x-2)
answer:
-5x+4
(-22 + 6) - (- 28 + 2)
(-16) - (-26)
-16 + 26
answer is 10.
Your equations would be
c+d=10
5c+6d=56 (c= # of cats, d= # of dogs) Then solve
I am using elimination and multiply the first equation by -5
-5c-5d=-50
5c+6d=56
Then eliminate
-d=-6 Divide by -1 d=6
Then solve for c
c+6=10
c=4
Hope this helps!
