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chubhunter [2.5K]
3 years ago
7

Find the probability of rolling a sum of 10 or a sum that is an odd number when two number cubes are rolled.

Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

7/12 chance

Step-by-step explanation:

(1 2 3 4 5 6)

(1 2 3 4 5 6)

All the possibilities:

(1, 1) (2, 1) (3, 1) (4, 1) (5, 1) (6, 1)

(1, 2) (2, 2) (3, 2) (4, 2) (5, 2) (6, 2)

(1, 3) (2, 3) (3, 3) (4, 3) (5, 3) (6, 3)

(1, 4) (2, 4) (3, 4) (4, 4) (5, 4) (6, 4)

(1, 5) (2, 5) (3, 5) (4, 5) (5, 5) (6, 5)

(1, 6) (2, 6) (3, 6) (4, 6) (5, 6) (6, 6)

There are 18 odd sums.

(1, 1) (2, 1) (3, 1) (4, 1) (5, 1) (6, 1)

(1, 2) (2, 2) (3, 2) (4, 2) (5, 2) (6, 2)

(1, 3) (2, 3) (3, 3) (4, 3) (5, 3) (6, 3)

(1, 4) (2, 4) (3, 4) (4, 4) (5, 4) (6, 4)

(1, 5) (2, 5) (3, 5) (4, 5) (5, 5) (6, 5)

(1, 6) (2, 6) (3, 6) (4, 6) (5, 6) (6, 6)

There are 3 possibilities whose sums add up to 10.

Since there are 36 total possibilities and 21 numbers that fit the rule of having an odd sum or a sum of 10. There is a 21/36 chance or simplified, 7/12 chance.

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QveST [7]

Answer:

Therefore, the relation of the given ordered pairs does NOT represent a function as that x-coordinate values are repeated.

Step-by-step explanation:

We know that a relation is basically a set of input and output values, which are expressed in ordered pairs.

A relation may have any set of ordered pairs.

We also know that a function is a set of ordered pairs in which each x-element has only one y-element associated with it.

Consider the five ordered pairs

x                       y

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The relation is: {(–2, 1), (3, –4), (–2, –6), (4, 6), (5, 7)}

From the table, it is clear that x-coordinate values are repeated.

In other words, x = -2 twice.

Therefore, the relation of the given ordered pairs does NOT represent a function.

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