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NemiM [27]
3 years ago
10

Please show ALL work! Solve for x: log₂x+log₂(x-6)=4

Mathematics
1 answer:
Vlad [161]3 years ago
5 0
Answer: x = 8

---------------------------------------------
---------------------------------------------

I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)

log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2

Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.

Only x = 8 is a proper solution.

------------------------

You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)

So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed

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5x + 3 - 2x = 12 + 7x - 2 solution ??? SOMEONE HELPPP PLEASE !!
tensa zangetsu [6.8K]

Answer:

x = -7/4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

5x + 3 - 2x = 12 + 7x - 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                                                                                        3x + 3 = 7x + 10
  2. [SPE] Subtract 3x on both sides:                                                                    3 = 4x + 10
  3. [SPE] Subtract 10 on both sides:                                                                      -7 = 4x
  4. [DPE] Divide 4 on both sides:                                                                         -7/4 = x
  5. Rewrite:                                                                                                           x = -7/4

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                     5(-7/4) + 3 - 2(-7/4) = 12 + 7(-7/4) - 2
  2. Multiply:                                -35/4 + 3 + 7/2 = 12 - 49/4 - 2
  3. Add:                                      -23/4 + 7/2 = 12 - 49/4 - 2
  4. Add:                                      -9/4 = 12 - 49/4 - 2
  5. Subtract:                               -9/4 = -1/4 - 2
  6. Subtract:                               -9/4 = -9/4

Here we see that -9/4 does indeed equal -9/4.

∴ x = -7/4 is the solution to the equation.

8 0
3 years ago
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