LM = 23
MN = 17
QR = 46
MR = 23
The measurements of your shape are not accurate considering a few things so I’m not sure how they expect you to answer correctly on one of them...
Answer:
0.34134
Step-by-step explanation:
in other to solve for this question we would be using the z score formula
z = (x - μ) / σ
x = raw score
μ = mean
σ = standard deviation
the question tells us to find the probability that a worker selected at random makes between $350 and $400
let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.
z1 = (x1 - μ) / σ = (350-400) / 50 = -1
z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0
from tables, P(z <= -1) = 0.15866
P(z <= 0) = 0.5
then the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =
0.34134
that explains that the probability that a worker selected at random makes between $350 and $400 = 0.34134
Place a point on positive 3 and go up one and over one then do the opposite so down one over one, since the sign does not have an or equal to symbol, it will be a dotted/dashed line. shade the part that is greater than positive three. to find out if your answer makes sense, place a dot anywhere on the graph to see if it goes with your answer.
Answer:
0.2
Step-by-step explanation:
Given the data :
Day : Mon Tue Wed Thu Fri Sat Sun
# of sick days 22 11 16 17 21 28 25
The expected count of sick days taken on Saturday is obtained thus :
Expected count = (row total * column total) / overall total
Here, the table is just one way :
Hence, we use :
Observed value / total days
Hence,
Expected count on Saturday = sick days on Saturday / total sick days
Expected count on Saturday = 28 / (22+11+16+17+21+28+25)
Expected count on Saturday = 28 / 140
= 0.2
Answer:
do length divided by width times height