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3 years ago

An equation that passes through (0, -2/3) and (-3, -2/3)

Mathematics

1 answer:

9966 [12]3 years ago

8 0

Answer:

y = 0x - 2/3

Step-by-step explanation:

We are asked to find the equation of the line

Step1: find the slope

( 0 , -2/3) ( 3 , -2/3)

m = (y_2 - y_1 )/ (x_2 - x_1)

x_1 = 0

y_1 = -2/3

x_2 = 3

y_2 = -2/3

Insert the values into the equation

m =( -2/3 - (-2/3) / (3 - 0)

= -2/3 + 2/3 / 3

= 0 / 3

m = 0

Step 2: sub m into the equation

y = mx + c

y = 0x + c

Step 3: sub any of the two points given into the eqn

y = 0x + c

Let's pick ( 3 , -2/3)

x = 3

y = -2/3

-2/3 = 0(3) + c

-2/3 = 0 + c

c = -2/3

Step4: sub c into the equation

y = mx + c

y = 0x + c

y = 0x - 2/3

Therefore, the equation of the line is

y = 0x - 2/3

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Answer:

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use formula for calculating the Variance:

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4 years ago

What is the precent of 2 is 8?

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2 * x/100 = 8

x/100 = 4

x = 400

400%

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3 years ago

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Answer:

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Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0, 2)

MrMuchimi

Answer:

y = -2x + 2

General Formulas and Concepts

Pre-Alg

Order of Operations: BPEMDAS

Algebra I

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-1, 4)

y-intercept (0, 2)

Step 2: Find slope m

Substitute: $m=\frac{2-4}{0+1}$
Subtract/Add: $m=\frac{-2}{1}$
Divide: $m=-2$

Step 3: Write linear equation

y = -2x + 2

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