Answer:
a14 = -40,960
Step-by-step explanation:
The sequence has a first term of 5 and a common ratio of -10/5 = -2, so the n-th term is given by ...
an = a1·r^(n-1)
an = 5·(-2)^(n-1)
The 14th term is then ...
a14 = 5·(-2)^(14-1) = -5·2^13 = -5·8192
a14 = -40,960
Answer:
![(-\infty, -5] \cup (4,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-5%5D%20%5Ccup%20%284%2C%5Cinfty%29)
Step-by-step explanation:
The symbol
is set notation for UNION--put two sets together into one set.
The first part of the interval notation describes x less than or equal to -5 -- notice the bracket symbol after -5, meaning include -5.
Hi there!
The formula to find the are of a circle is :
a =
r²
The formula to find the circumference of a circle is :
c = 2
r
In order to use the area formula, you need to figure out what the radius (r) is.
If we solve for "r" in the circumference equation, we have :
r = c ÷ (2
)
Now we use this to replace "r" in the area formula :
a =
( c ÷ (2
))²
When we simplify this we get :
a = c² ÷ 4
Now you can put your value of "c" into this equation and find "a".
*Remember,
is about 3.1416.
Solving for "a" :
a = c² ÷ 4
a = 28² ÷ 4
28² = 28 × 28 = 784
a = 784 ÷ 4
4
= 4 ×
= 12.56637061435917
a = 784 ÷ 12.56637061435917
a = 62.38873769202297cm²
You need to round to the nearest square centimeter, which means that you need to round to the nearest whole number :
a = 62cm²
There you go! I really hope this helped, if there's anything just let me know! :)
Answer: 
Step-by-step explanation:
For this exercise it is important to know the definition of "Dilation".
A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.
If the Dilation is centered at the origin, and knowing the scale factor of
, you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.
Knowing that the point T has the following coordinates:

You get that the coordinates of the Image T' are the shown below:

The answer is f^-1(x)=8/3+x/3