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Taya2010 [7]
3 years ago
7

Let x denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. suppose t

hat for banner-tailed kangaroo rats, x has an exponential distribution with parameter λ = 0.01382. (a) what is the probability that the distance is at most 100 m? at most 200 m? between 100 and 200 m? (round your answers to four decimal places.)
Mathematics
1 answer:
forsale [732]3 years ago
4 0

To solve this problem, we have to use the formula:

P = 1 - e^(-λx)

<span>where λ = 0.01382, and x is the  distance</span>

 

A. when x = 100

(P < or equal to 100) = 1 - e^(-0.01382 * 100)

(P < or equal to 100) = 0.75 


B. when x = 200
<span>(P < or equal to 200) = 1 - e^(-0.01382 * 200)
(P < or equal to 200) = 0.94</span>

 

C. when 100 < x < 200
P (100 < x < 200) = P ((x < 100) + P(x > 200)) 
P (100 < x < 200) = 0.75 + (1 – 0.94)

<span>P (100 < x < 200) = 0.81 </span>

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