The conjugate which is 3 - √7 is also a root of f(x).
<h3>What is the root of a polynomial function?</h3>
The root of a polynomial function f(x) is the value of x for which f(x) = 0.
Now if a polynomial function has a root x = a + √b then the conjugate of x which is x' = a - √b is also a root of the function, f(x).
<h3>What must also be a root of f(x)?</h3>
Given that the polynomial function, f(x), with rational coefficients has roots
3 + √7, then by the above, the conjugate which is 3 - √7 is also a root of f(x).
So, 3 - √7 is also a root of f(x).
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Answer:
an= 12 + (-6)(n-1)
Step-by-step explanation:
you should find two values: a1 and d
a1= first number =12
d= a number of the sequence mines the number of the sequence before the one you chose = 0-6 = -6
a1+(n-1)d= 12-6(n-1)
A - 4
B - 10
looking for the LCM (least common multiple)
4 and 10 can both be divided evenly into 20
20 = LCM
Since the triangle is 45,45,
90 arrangement. We can use the special triangle trick. Which gives us 2,2 and square root of 2 times 2