If you would like to know what is the product of (6 * x^3 + 3 * x) * (x^2 + 4), you can calculate this using the following steps:
(6 * x^3 + 3 * x) * (x^2 + 4) = 6 * x^3 * x^2 + 6 * 4 * x^3 + 3 * x * x^2 + 3 * 4 * x = 6 * x^5 + 24 * x^3 + 3 * x^3 + 12 * x = 6 * x^5 + 27 * x^3 + 12 * x
The correct result would be 6 * x^5 + 27 * x^3 + 12 * x.
Your goal is to isolate the x variable, so all you have to do here is subtract 6 on both sides.
Your final answer is x ≤ 2.
Hope this helps a lot! :)
Step-by-step explanation:
Geometric series.
Month 3.
100(1+\frac{0.02}{12})^2 + 100(1+\frac{0.02}{12})+100
Month 4.
100( 1 + \frac{0.02}{12})^3 + 100( 1 + \frac{0.02}{12})^2+100(1+\frac{0.02}{12})+100
Month 5.
100(1 + \frac{0.02}{12})^4 + 100(1 + \frac{0.02}{12})^3 + 100(1 + \frac{0.02}{12})^2 +100( 1 + \frac{0.02}{12}) + 100
C(t) = $2t + $8
This tells us that the basic cost of the pizza is $8, with no toppings, and that each topping costs an additional $2.
To graph this, plot a dot at (0,$8). Now move y our pencil point 1 unit to the right and then 2 units up. Plot a dot at this new location. Now draw a straight line connection (0, $8) and this new location (which is (1, $10) ).
