Y=2x + 3
The slope is 2, because when graphed, it’d be up two over one. And the y-intercept is 3 because the point on the y-axis is (0,3)
Step 1:
Put the information given in the word problem into the equation p(x)=0.09x+c. So plug in 1,570 for x and 490.30 for p(x).
490.30 = 0.09 (1,570) + c
490.30 = 141.3 +c
-141.3 -141.3
--------------------------------------
349 = c
Step 2: Check your work!
490.30 = 0.09 (1,570) + 349
490.30 = 141.3 + 349
490.30 = 490.30
A. 2u+4<2 => u+2<1 => u<-1
B. 4u+1 < 21 => 4u < 20 => u<5
Here we need to combine the two inequalities, namely check for overlaps before writing in interval notation.
since u<-1 is already part of u<5, the solution set is u<-1, since u=0 (for example) will not satisfy the first inequality.
we write in interval notaion:
(-inf, -1)
the parentheses ( or ) mean the value closest to it is excluded.
the two values are the lower and upper bounds of the interval.
Here we mean the solutions are from -infinity (but excluded, because infinity is not a number) all the way up to -1, but -1 is also excluded because of the sign < (and not <=).
If the boundary value is to be included, we use the bracket.
For example, u<=-1 would be (-inf, -1].
Answer:
x=y[base side of isosceles triangle]
x²+y²=19²
x=√{19²/2)}
x=13.44
y=13.44