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tekilochka [14]
3 years ago
15

But The aquarium charges $12 per ticket for adults and $5per ticket for children. A group of 90 children and adult chaperones vi

sited the aquartum on a held trip. If the total cost of their tickets was $548, how mamy chaperones were there?
Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

There were 76 childrens and 14 adults.

Step-by-step explanation:

Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:

children + adults = 90

Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:

5*children + 12*adults = 548

With these two equations we have a system of equations shown below:

children + adults = 90

5*children + 12*adults = 548

In order to solve this we will multiply the first equation by -5, and sum both equations we have:

-5*children - 5*adults = -450

5*children + 12*adults = 548

7*adults = 98

adults = 98/7 = 14

children + 14 = 90

children = 90 - 14 = 76

There were 76 childrens and 14 adults.

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3 years ago
The mean of 40 observations was 160. It was detected on rechecking that the salue of
Ierofanga [76]

Answer: The correct mean is 161.

Step-by-step explanation: The question states that we have computed the mean of 40 observations and the mean is 160. This means the set of data altogether is 40 numbers. In order to arrive at the mean, we must have added all 40 observed data to get the summation of observed data and divided this by 40. In other words, we must have done something like,

Mean = {Summation} x/{x}

Where x = 40 and the mean computed is 160.

Therefore,

160 = {summation}x/40

By cross multiplication we now have

160 (40) = {summation} x

6400 = {summation}x.

However, we must not forget that one of the values in the observed data was wrongly copied as 125, (instead of 165). What this means is that the summation of all observed data is having a shortage of 40 (that is, 165 - 125). If we now insert the correct figure of 165 in place of the wrong one which is 125, our summation of observed data would now become 6440 (the shortage of 40 would have been added back to 6400).

What we now have is

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7 0
3 years ago
(section 6.1) Find the length of the small arc formed by the intersection of the unit circle a circle centered at the origin wit
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Answer:

The length of the arc is approximately 2.0944

Step-by-step explanation:

The given parameters are;

The equation of the circle = x² + y² = 1

The radius of the circle, r = 1

The equation of the line, y = 1/2

Therefore, we point where the line intersects with the circle are given as the points 'y = 1/2' as follows;

When y = 1/2, the equation of the circle becomes;

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The angle subtended by the arc, θ = 2 × arctan((√3/2)/(1/2)) = 120°

The circumference of the circle, C = 2·π·r

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The length of the arc, l = (θ/360) × C

∴ l = (120/360) × 2·π = (2/3)·π

The length of the arc, l = (2/3)·π ≈ 2.0944

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3 years ago
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aleksklad [387]
Well assuming that the Pool doesn't have a limit on the amount of gallons of water it can hold

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