Substitute y=4x to the second equation:
x^2 + (4x)^2 = 17
x^2 + 16x^2 = 17
17x^2 = 17
x^2 = 17/17
x^2 = 1
x = 1 and -1
When x=1, y=4(1) = 4
When x=-1, y=4(-1) = -4
Thus the solutions would be (1,4) and (-1,-4). That would correspond to D. and A.
Answer:
Part a) ![T(d)=2d+30](https://tex.z-dn.net/?f=T%28d%29%3D2d%2B30)
Part b) ![T(6)=42\ minutes](https://tex.z-dn.net/?f=T%286%29%3D42%5C%20minutes)
Step-by-step explanation:
Part a) Write an equation for T (d)
Let
d ----> the number of days
T ---> the time in minutes of the treadmill
we know that
The linear equation in slope intercept form is equal to
![T=md+b](https://tex.z-dn.net/?f=T%3Dmd%2Bb)
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem we have
The slope or unit rate is
![m=2\ \frac{minutes}{day}](https://tex.z-dn.net/?f=m%3D2%5C%20%5Cfrac%7Bminutes%7D%7Bday%7D)
The y-intercept or initial value is
![b=30\ minutes](https://tex.z-dn.net/?f=b%3D30%5C%20minutes)
substitute
![T(d)=2d+30](https://tex.z-dn.net/?f=T%28d%29%3D2d%2B30)
Part b) Find T (6), the minutes he will spend on the treadmill on day 6
For d=6
substitute in the equation and solve for T
![T(6)=2(6)+30](https://tex.z-dn.net/?f=T%286%29%3D2%286%29%2B30)
![T(6)=42\ minutes](https://tex.z-dn.net/?f=T%286%29%3D42%5C%20minutes)
Two and one eighth is the answer
Answer:
try A
Step-by-step explanation: