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Anton [14]
3 years ago
8

Help meeeeee

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

1) 1/3

2) x/y +8

3) x*2+13

4) x+10

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Timmy is in the mall with his mom, and is throwing a fit because he wants her to buy him a new
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X=4

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ALGEBRA 2 FINALS
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8 0
3 years ago
In a sample of 800 U.S. adults, 218 dine out at a restaurant more than once a week. If two U.S adults are selected at random fro
andre [41]

Answer: 0.074

Step-by-step explanation:

Given : The total number of U.S. adults in the sample = 800

The number of U.S. adults dine out at a restaurant more than once a week = 216

The probability for an adult dine out more than once per week :-

\dfrac{218}{800}

If another person is selected without replacement ,then

Total adults left = 799

Total adults left who dine out at a restaurant more than once a week = 217

The probability for the second person dine out more than once per week :-

\dfrac{217}{799}  

Now, the probability that both adults dine out more than once per week :-

\dfrac{218}{800}\times\dfrac{217}{799}=0.074

3 0
3 years ago
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