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3 years ago

Half-life formula: A = A0(0.5) t/h

Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

Answer: the answer is 4

Step-by-step explanation:

when looking for the half life, it says to look for when the initial amount is half of what it used to be, because it is 100, 100 divided by 2 is 50, and when looking at the hours (x value) for 50 it says 4.

Temka [501]3 years ago

3 0

Answer:

4 hours

Step-by-step explanation:

on edge 2020

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3 years ago

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Brums [2.3K]

Answer:

it as actually 5 soo.

Step-by-step explanation:

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3 years ago

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A car travels 106.2 miles in 2.3 hours

melisa1 [442]

Answer:

Kawaii, the problem is the comparison with the calculated time for Jillian and the actual time for Jillian to run the 7 miles.

%error=(calculated value - experiemental value)/calculated * 100%

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Note: 16% error is the approximate error because the numbers have 2 significant figures stated in the problem.

Step-by-step explanation:

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3 years ago

Which of the following pairs of functions are inverses of each other?

natta225 [31]

Answer:

The pair which are inverse of each other are:

Option: C

$f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}$

Step-by-step explanation:

Two functions f(x) and g(x) are said to be inverse of each other if:

fog(x)=gof(x)=x

i.e. the composition of two functions give identity no matter what the order is.

$f(x)=\dfrac{x}{12}+15$ and $g(x)=12x-15$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(12x-15)\\\\fog(x)=\dfrac{12x-15}{12}+15\\\\fog(x)=x-\dfrac{15}{12}+15\\\\fog(x)=x-\dfrac{55}{4}\neq x$

Hence, option: A is incorrect.

$f(x)=\dfrac{3}{x}-10\ and\ g(x)=\dfrac{x+10}{2}$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+10}{3})\\\\fog(x)=\dfrac{3}{\dfrac{x+10}{3}}-10\\\\fog(x)=\dfrac{9}{x+10}-10\neq x$

Hence, option: B is incorrect.

$f(x)=9+\sqrt[3]{x}\ and\ g(x)=9-x^3$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(9-x^3)$

$fog(x)=9+\sqrt[3]{9-x^3}\neq x$

Hence, option: D is incorrect.

$f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+4}{11})$

$fog(x)=11\times (\dfrac{x+4}{11})-4\\\\fog(x)=x+4-4\\\\fog(x)=x$

Similarly,

$gof(x)=g(f(x))\\\\gof(x)=g(11x-4)\\\\gof(x)=\dfrac{11x-4+4}{11}\\\\gof(x)=\dfrac{11x}{11}\\\\gof(x)=x$

Hence, option: C is the correct option.

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3 years ago

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