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kkurt [141]
3 years ago
10

Find the perimeter of the given shape.

Mathematics
1 answer:
vodomira [7]3 years ago
6 0

Answer:

36

Step-by-step explanation:

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48 divided by 6 - 3 3/4
nordsb [41]

Answer:

4/1/4

Step-by-step explanation:

48÷6

=8-3 3/4

=4/1/4

8 0
3 years ago
Read 2 more answers
(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
3 years ago
Convert 3/18 to a decimal
frutty [35]
3/18 = 0.166667

hope this helps . 
3 0
3 years ago
Read 2 more answers
Find 3 things in the kitchen that you can measure the temperature of with degrees
alexandr402 [8]
Stove, oven, thermometer.
3 0
3 years ago
Read 2 more answers
Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?
BigorU [14]
We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

( x^{2} +2xy + y^{2} ), multiplied by the last "x+y".

x^{3} +3 x^{2} y +3x y^{2} + y^{3}

Coefficients are the number that comes in front of a variable. 

In this case, 1 comes in front of x^{3}, 3 comes in front of x^{2} y, 3 comes in front of x y^{2}, and 1 comes in front of y^{3}.

Thus: 1, 3, 3, 1.
         Answer Choice A
4 0
3 years ago
Read 2 more answers
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