8.9mm/10 = 0.89cm. since 10mm is 1 cm.
Answer:
T = 88 -(7/2000)A
Step-by-step explanation:
The table values have a constant difference of +2000 ft and -7 degrees, so the slope of the linear equation is -7/2000 degrees per ft. The temperature is 88 at an altitude of 0, so we can write the requested equation in slope-intercept form as ...
T = 88 -(7/2000)A
_____
The slope-intercept form of the equation for a line is ...
y = mx + b
where m is the slope and b is the y-intercept. In this equation, y is the dependent variable and x is the independent variable. For our temperature equation, the dependent variable is T, and the independent variable is A.
The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)b−a.
We have that a=1254, b=6103100, f(x)=20(54)x.
Thus, f(b)−f(a)b−a=20(54)(6103100)−(20(54)(1254))6103100−(1254)=−58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100.
Answer: the average rate of change is −58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100≈550754.870532511
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Kevin would have to write 133 problems, as 14/5= $2.8 per problem 370/2.8= 132.14 but since he can’t be paid to write .14 of a problem he needs to finish it making the answer 133 problems
