Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
77.) x= {-5, 6}
78.) x= {-4, 9}
79.) x= {5/3, 2}
80.) x= {1/9, 3}
81.) x= {-6, 18}
82.) x= {-3√3 +4, 3√3 +4}
83.) x= {-7, -3}
84.) x= {-√85 +9 /2, √85 -9 /2}
9514 1404 393
Answer:
JKT, JLT, KLT
Step-by-step explanation:
Each of the given bisectors is the altitude of an isosceles triangle. Those triangles are ...
JKT
JLT
KLT
Answer:
The equation that matches the table is y = -5x + 7 ⇒ C
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept (value y at x = 0)
The rule of the slope is m =
, where
- (x1, y1) and (x2, y2) are two points on the line
From the given table
→ Choose any two points from the table
∵ Points (0, 7) and (1, 2) are in the table
∴ x1 = 0 and y1 = 7
∴ x2 = 1 and y2 = 2
→ Substitute them in the rule of the slope above
∵ m = 
∴ m = -5
→ Substitute it in the form of the equation above
∵ y = -5x + b
∵ b is the value of y at x = 0
∵ At x = 0, y = 7
∴ b = 7
∴ y = -5x + 7
∴ The equation that matches the table is y = -5x + 7
Answer:
$16, sorry if its wrong (im pretty sure i'm right tho)