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3 years ago

8

Which is the biggest fraction? 2/4 2/3 4/5 4/6

1 answer:

son4ous [18]3 years ago

4 0

The biggest fraction would be 4/5

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A certain shade of green paint is made from 5 parts yellow mixed with three parts blue. If 2 cans of yellow are used, how many c

vekshin1

5 Yellow = 3 Blue
2 Yellow = 3/5 *2 = 6/5 Blue, 1.2 cans of Blue .
<u>Award brainliest if helped!</u>

6 0

3 years ago

A number is between 16 and 21. It has prime factors of 2, and 3. What is the number?

Advocard [28]

Answer:18

Step-by-step explanation: 18=2.3.3

6 0

3 years ago

WARNING : NON SENSE ANSWER REPORT TO MODERATOR

Rzqust [24]

Answer:

$\frac{180}{147}$

Step-by-step explanation:

Simplify $(\frac{3}{-7} - \frac{11}{21} )$

$=> \frac{(-3 \times 3) - 11}{21}$

$=> \frac{-9 - 11}{21}$

$=> \frac{-20}{21}$

Find the additive inverse of $\frac{-20}{21}$ by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of $\frac{-20}{21}$ .

$=> x + \frac{-20}{21} = 0$

$=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}$

Simplify $(\frac{9}{5} \div \frac{7}{5} )$

$=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }$

$=> \frac{9}{5} \times \frac{5}{7}$

$=> \frac{9}{7}$

Now, find the product of $\frac{9}{7}$ & $\frac{20}{21}$

$=> \frac{9}{7} \times \frac{20}{21}$

$=> \frac{180}{147}$

3 0

3 years ago

Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

3 0

3 years ago

Rectangle ABCD was dilated to create rectangle A'B'C'D.

77julia77 [94]

The first thing we must do for this case is to calculate the scale factor.

For this, we make the relationship between two parallel sides.

We have then:

$k =\frac{B'C'}{BC}$

Substituting values we have:

$k = \frac{9.5}{3.8}\\k = 2.5$

We are now looking for the value of AB

We have then:

$AB = \frac{A'B'}{k}$

Substituting values:

$AB = \frac{15}{2.5}\\AB = 6$

Answer:

The scale factor is:

$k = 2.5$

The value of AB is:

$AB = 6$

8 0

3 years ago

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