We take the value of F in the inequality by taking the inequalities in group. Let the first group be:
(1) -20 ≤ 59(F - 32)
Then, the second group would be,
(2) 59(F - 32) ≤ - 15
Calculating for the values of F,
(1) -20 ≤ 59F - 1888
1888 - 20 ≤ 59F
1868 ≤ 59F
F ≥ 31.66
(2) (59)(F - 32) ≤ - 15
59F - 1888 ≤ -15
59F ≤ 1873
F ≤ 31.75
The values of F are therefore,
31.66 ≤ F ≤ 31.75
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
yes it is greater than 2/5
