All categories

3 years ago

Sound travels about 335 meters/second. How many kilometers would a sound travel in 1 minute?

1 answer:

7 0

If sounds travel 335 meters in 1 second , in 1 minute it travels 60 times that distance :

335m × 60 = 20100 meters
Sounds travel 20100 meters per minute
if 1000 meters = 1 km ,
20100 meters = 20100/1000 km
20100 meters = 20.1 Km

Awnser : Sound would travel 20.1 km in one minute

You might be interested in

Which is the factorization of 8x2 + 13x – 6

pashok25 [27]

Answer:

(8x−3)(x+2)

Step-by-step explanation:

Factor 8x2+13x−6

8x2+13x−6

=(8x−3)(x+2)

5 0

3 years ago

Read 2 more answers

Write a paragraph proof that 1+1=2<br> (Fun fact: it took over 72 pages just to prove that 1+1=2)

Irina18 [472]

Answer:

The theorem here is essentially that

if a and 3 are disjoint sets with

exactly one element each, then their

union has exactly two elements. ...

Peano shows that it's not hard to

produce a useful set of axioms that

can prove 1+1=2 much more easily

than Whitehead and Russell do.

3 0

3 years ago

Read 2 more answers

Priscilla’s grandmother’s fruit salad recipe calls for one part apple, one part orange, four parts strawberry, two parts cherry,

damaskus [11]

Answer:

There are 11 parts of fruit: 4-strawberry, 3- grape, 2, cherry, 1- apple, 1-orange 4/11 from the entine quantity of fruits- strawberry

3/11-grapes

2/11- cherries

1/11- apples

1/11- oranges } ⇒ the quantity of oranges and apples are equal Hope it helps ;>

6 0

3 years ago

Bob's carpet cleaning company uses the equation y=22x+30 to calculate cost, y, to clean x numbers of rooms. Andy's carpet cleani

olga_2 [115]

Bob charges $140
Andy charges $135
Andy is cheaper

6 0

4 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Dmitriy789 [7]

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18 true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18 false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4 True

7 0

3 years ago

Read 2 more answers