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Bezzdna [24]
3 years ago
11

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
7 0

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18  true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18   false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is  symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4  True

ANTONII [103]3 years ago
7 0

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

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BartSMP [9]

Step-by-step explanation:

3cos2x +sinx=1

3(1-2sin²x)+sinx=1

3-6sin²x+sinx=1

sinx(-6sinx+1)=1

either

sinx=1

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:.x=90

or

-6sinx+1=1

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8 0
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Lostsunrise [7]

Answer:

a) x(x+2)

b) 2x(x-3)

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Step-by-step explanation:

a) x^2+2x

When factoring a binomial (a polynomial with two terms), what we will be looking for are the terms that are shared between them.

In this problem, it can be seen that both of these terms have and x. This means that we can factor it out to get

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Fiesta28 [93]
X = number of servers
y = number of guests

\text {number of guest per table = } 4<span>

</span>\text {number of tables = } \dfrac{y}{4}
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