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saveliy_v [14]
3 years ago
9

Slope of 2/5 that passes through (10,-4)

Mathematics
2 answers:
nadya68 [22]3 years ago
5 0
F(x)=2/5-4
i hope this helps

olga2289 [7]3 years ago
4 0
Y + 4 = 2/5(x - 10)
y + 4 = 2/5(x) - 4
y = 2/5(x) - 8

hope it helps
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The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch
DedPeter [7]

Answer:

The surface area is equal to 390\ in^{2}

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

so

In this problem

SA=4[\frac{1}{2}(b)(h)]

we have

b=15\ in

h=13\ in

substitute the values

SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}

4 0
3 years ago
Read 2 more answers
What statement apply to ratio of rice and water? Choose two
adell [148]

Answer:

Step-by-step explanation: The amount of water is the dependent value

7 0
3 years ago
Solve the equation by completing the square. If necessary, round to the nearest hundredth.
diamong [38]
Ax^2+bx=c
REMEMBER THIS

ok
first, make sure that a is 1
done

now take 1/2 of b and square it

-18/2=-9, (-9)^2=81
add that to both sides

x²-18x+81=19+81
x²-18x+81=99
factor perfect square
(x-9)²=100
square root both sides
don't forget positive and negative root
x-9=10
x-9=-10
ad 9 to both sides

x=19
x=-1




answer is -1; 19

2nd choice is answer
8 0
4 years ago
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Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)
Tems11 [23]

The slope of the tangent line to f at x=-1 is given by the derivative of f at that point:

f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}

Factorize the numerator:

2x^2-2=2(x^2-1)=2(x-1)(x+1)

We have x approaching -1; in particular, this means x\neq-1, so that

\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)

Then

f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4

and the tangent line's equation is

y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2

6 0
3 years ago
The length of a rectangular mailing
anygoal [31]

<em><u>ANSWER</u></em>

Let the width be y

2(L + W) = Perimeter

2(2y - 5cm + y) = 62cm

(2×2y) + (2×-5cm) + (2×y) = 62cm

4y + - 10cm + 2y = 62cm

4y - 10cm + 2y = 62cm

4y + 2y - 10cm = 62cm

6y - 10cm + 10cm = 62cm + 10cm

<u>6</u><u>y</u> = <u>7</u><u>2</u><u>c</u><u>m</u>

6 6

y = 12cm

<em><u>WIDTH</u></em>

= y

= 12cm

<em><u>LENGTH</u></em>

= 2y - 5cm

= 2×y - 5cm

= 2×12cm - 5cm

= 24cm - 5cm

= 19cm

<em><u>Providence</u></em>

19cm + 19cm + 12cm + 12cm = 62cm which is the perimeter

7 0
3 years ago
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