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german
3 years ago
12

darcy is finding the product of 11 and 17 using the distributive property. she set up the problem as 11 × (10 7). what would she

do next?
Mathematics
2 answers:
Helen [10]3 years ago
7 0
Multiply 11 times 10 and 11 times 7
zheka24 [161]3 years ago
4 0

Answer:

8idt10, you are correct!

Step-by-step explanation:

You have already been given the answer! Great job! Good luck!

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The graph shows the 2005 median income of some year-round workers and the number of years of school. Estimate the median income
xxTIMURxx [149]

Answer:20??

Step-by-step explanation:

4 0
3 years ago
What is the cost of 20pens is rs 1200,what is the cost of one pen​
myrzilka [38]

Answer:

rs 60

1200/20=60......

3 0
2 years ago
Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int
navik [9.2K]

Answer: 28\ cubes

Step-by-step explanation:

The volume of a cube can be found with this formula:

V_{(c)}=s^3

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

V_{rp}=lwh

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3

To find the volume of the shipping box, first we must convert the mixed number to  an improper fraction:

1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}

Then the volume of the shipping box is:

V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3

Now, in order to find the  number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28

6 0
3 years ago
Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
3 years ago
What is <br> Multiple of 10
Vadim26 [7]
10,20,30,40,50,60,70,80,90,100….etc
4 0
3 years ago
Read 2 more answers
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