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german
3 years ago
12

darcy is finding the product of 11 and 17 using the distributive property. she set up the problem as 11 × (10 7). what would she

do next?
Mathematics
2 answers:
Helen [10]3 years ago
7 0
Multiply 11 times 10 and 11 times 7
zheka24 [161]3 years ago
4 0

Answer:

8idt10, you are correct!

Step-by-step explanation:

You have already been given the answer! Great job! Good luck!

You might be interested in
24+82 rounding or compatible numbers to estimate the sum
allsm [11]

Answer:

106

Step-by-step explanation:

you take 82 and 24 and add them together so it would be like this 2 + 4 = 6 and 8 + 2 = 10 so the 8 is in a tens place so the answer from adding 8 + 2 = 100 because you in the tens place so the final answer would be 106 after adding it all up.

4 0
2 years ago
Please help me branniest
Julli [10]

Answer:

just add the powers to get 6 to the 10 power


3 0
3 years ago
Find the area of this irregular polygon.
Rainbow [258]

Answer:

970m^{2}

Step-by-step explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:

At= \frac{b.h}{2}

Where:

H= height = 30 m

B = 9 m + 9 m + 20 m = 38 m

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.

At= \frac{38 m .30 m}{2}

At= \frac{1140 m^{2} }{2}

At= 570 m^{2}

Now we are going to calculate the square's area, that is much more simple:

As= L^{2}

Where:

L=20 m

As= (20 m)^{2} = 400m^{2}

To know the whole figure's area, we add up both areas:

A = At+As = 570m^{2} +400m^{2}=970m^{2}

3 0
3 years ago
If any of the graphs below have a Hamiltonian circuit, list the vertices of the complete circuit. There may be many possibilitie
german

9514 1404 393

Answer:

  1. ABHGEFDCA
  2. does not exist
  3. ECBADFE

Step-by-step explanation:

A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.

__

For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.

__

For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.

6 0
3 years ago
How many diagonals does a 12-sided convex polygon have? What is the general
mario62 [17]

Answer:

goodluck!

Step-by-step explanation:

well is 12 sided and has digonal so

8 0
3 years ago
Read 2 more answers
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