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8090 [49]
3 years ago
8

Karen has a large pile of colored rods. Each color is a different length. She is trying to connect different colored rods to mak

e triangles as part of a hanging sculpture. Here is a list of rod lengths.
Red: 3 inches
Orange: 4 inches
Yellow: 5 inches
Green: 7 inches
Blue: 9 inches
Purple: 12 inches


1. How many triangles can she make with them if each side is a different color? List the combinations that work.













2. Karen was just trying different combinations of colored rods one at a time, placing the colored rods together to see if they make a triangle. What method did you use to determine the triangle options? Which method do you think is better and why?
HELP
Mathematics
2 answers:
lesya [120]3 years ago
8 0

Answer:

RED,ORANGE,YELLOW

PURPLE,YELLOW,GREEN

BLUE,GREEN,YELLOW

PURPLE,BLUE,GREEN

PURPLE,BLUE,RED

PURPLE,ORANGE,BLUE

RED,YELLOW,BLUE,

ORANGE,YELLOW,GREEN

YELLOW,BLUE,PURPLE

YELLOW,GREEN,PURPLE

there is many combinations

Step-by-step explanation:

Romashka [77]3 years ago
5 0

If you are trying to figure out how many combinations there are just do 6x5x4x3x2x1

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1 whole one and a third of one.

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1 1/3 of a granola bar

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Nesterboy [21]

Answer:

40%

Step-by-step explanation:

Given the result of the simulation below:

(5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4)

(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)

n(S)=20

  • The numbers 0 to 6 represent a made free throw .
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Let Event A be the event that the player made both throws

The pairs in which the player made both throws are:

(5,5) (0,6) (0,4) (1,4) (5,3)  (3,5)  (2,1) (0,6)

n(A)=8

Therefore:

P(A)=\frac{n(A)}{n(S)}=\frac{8}{20}=0.4\\

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Let total money be m

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