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cestrela7 [59]
3 years ago
6

Find the inverse function. f (x)=1/2x+6

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

The inverse of this function is f(x) = 2x - 12.

You can find the inverse of any function by switching the f(x) and x values in the equation. Then you can solve for the new f(x) value. The result is your inverse function. The work for this one is below.

f(x) = 1/2x + 6 ----> switch f(x) and x

x = 1/2f(x) + 6 ----> subtract 6

x - 6 = 1/2f(x) ----> multiply by 2

2x - 12 = f(x) ----> change the order for consistency.

f(x) = 2x - 12

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Simplify the ratio 9/12
Alex777 [14]
3:4 This is the answer
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If two angles are complementary. One angle measures 22 degrees. And the other angle measures 2x degrees, what is the value of x?
levacccp [35]

Answer:

x=34

Step-by-step explanation:

34*2=68

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5 0
2 years ago
What is the range of possible values for x?
Talja [164]
The minimum value for 2x is 0 
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>

<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>

<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>

<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>

<span>sin 2x = 22 (sin 34°)/30 </span>

<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>

<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>

<span>0 < x < 12.1°</span>
7 0
3 years ago
Would you say that pythagoras’ theorem holds true for hexagons as well? why or why not
kifflom [539]
No, the Pythgorean Theorem only applies to right triangles. To get two right triangles, you divide a rectangle diagonally. Dividing a hexagon into two pieces produces trapezoids or pentagons depending where it is divided. 
7 0
3 years ago
Keith exercises x hours a week. Troy exercises three hours less than Keith and Joe exercises two times more than Troy. Which exp
umka21 [38]
If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3. 
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two. 

Keith = x
Troy = x-3
Joe = 2(x-3)
4 0
3 years ago
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