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zhenek [66]
3 years ago
12

What integer is equivalent to 25^3/2

Mathematics
2 answers:
natka813 [3]3 years ago
6 0
The answer is 125.  Hope this helps you. 
Ierofanga [76]3 years ago
4 0

Answer:

125.

Step-by-step explanation:

We are asked to find the integer equivalent to 25^{\frac{3}{2}}.

We can rewrite 25 as 5^2.

(5^2)^{\frac{3}{2}}

Using exponent property (a^{b})^c=a^{b\times c}, we will get:

(5^2)^{\frac{3}{2}}=5^{2^\times\frac{3}{2}}

(5^2)^{\frac{3}{2}}=5^{3}

(5^2)^{\frac{3}{2}}=125

Therefore, 125 is equivalent to our given number.

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Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

s_{Md}=\sqrt{\frac{2MSE}{n_h}}

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MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

The weighted sample size nh can be calculated as

n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16

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s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

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Answer:

Step-by-step explanation:

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