1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sasho [114]
3 years ago
8

Planes flies 2951 miles in 6.5 hours what is the speed of the airplane miles per hour

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0
2951mi/6.5 h = 454 mph

pantera1 [17]3 years ago
3 0
Divide 2951 by 6.5 to get the answer
You might be interested in
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
Does anyone understand this
Nataliya [291]

For this problem, 0.25 in = 50 m. So

11 in = (11 in) • (50/0.25 m/in) = 2200 m

Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.

3 0
3 years ago
0.3(5x - 1.5) = 7.5 x= ?
vfiekz [6]

Answer:

x=5.3

Step-by-step explanation:

.3(5x-1.5)=7.5

1.5x-.45=7.5

1.5x=7.95

x=5.3

6 0
3 years ago
Which equation represents this line in point slope form -3,4 -3,4
spin [16.1K]

Answer: <em>I think the answer is 5</em>

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP ME!!!!! WHAT IS 4+4
Volgvan
The answer is eight
8 0
3 years ago
Read 2 more answers
Other questions:
  • The Burns family went to breakfast at the huddle house. Mr. Burns ordered a meal for $7.75, Mrs. Burns ordered a meal for $ 9.50
    14·2 answers
  • Which phrase describes the algebraic expression StartFraction 7 over 8 EndFraction y minus 3?
    9·2 answers
  • If A = 4 what is the value of the expression 12 - a/4
    11·2 answers
  • Need help with a math question
    15·1 answer
  • Six plus four times a number plus four times four minus four times the number no
    5·1 answer
  • A company rents riding equipment for a fixed amount plus a fee based on the number of days for which the equipment is rented. Th
    6·1 answer
  • Convert 96.4% to a fraction in simplest form and a decimal.
    15·1 answer
  • Kellen got an e-mail from his bank on June 7th, June 21st, July 5th, and July 19th. Use inductive reasoning to predict the next
    14·2 answers
  • Find the output, y, when the input x, is 30.<br> y = 14 – 0.5x<br> y =
    6·1 answer
  • 33 point ;)<br> umm its not hard
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!