Answer:
x²+6x+5=0
On comparing with the equation
ax² + bx + c = 0
a=1, b = 6 and c = 5
Now
b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16
When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced when potass
ium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the product mixture. However, when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the product mixture. What percent of 2-methyl-1-butene would be in the mixture if potassium propoxide were the base?
1 answer:
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