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Nataliya [291]
3 years ago
9

What is 10x20=???????????? I NEEED HELP

Chemistry
1 answer:
pochemuha3 years ago
5 0

Answer:

The answer for 10 times 20 is 200

Explanation:

Why... Because what is 1 times 2=2 so add the left over zero I'm that your answer!

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What is the mass percent of aluminum in Al(OH)3 the molar mass of AL = 26.98, H = 1.0079, and O = 16.00
LiRa [457]
Mass percentage = (mass of Al)/(Total mass) * 100
= (26.98) / (26.98 + 3 * (1.0079 + 16)) * 100
= 34.59%
7 0
3 years ago
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A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

3 0
3 years ago
A 20.0 ml sample of glycerol has a mass of 25.2 grams. What is the mass of 63 ml sample of glycerol?
poizon [28]

The mass of 63 ml sample : 79.38 g

<h3>Further explanation</h3>

Given

20 ml and 25.2 g of glycerol

Required

The mass of 63 ml sample

Solution

Density is the ratio of mass per unit volume

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}

Density of glycerol :

= m : V

= 25.2 g : 20 ml

= 1.26 g/ml

Mass of 63 ml sample :

= density x volume

= 1.26 g/ml x 63 ml

= 79.38 g

7 0
3 years ago
Hydrated copper sulphate is a blue crystalline solid. When heated, it changes to anhydrous copper sulphate, a white powder. What
777dan777 [17]
<span>Hydrated copper sulphate  means containing water.
</span><span> Anhydrous copper sulphate means water was removed.

Answer: </span><span>a. LOSS OF WATER.</span>
7 0
3 years ago
A negatively charged particle is attracted to A. All particles that are located close by. B. Only particles that are large. C. N
Dahasolnce [82]

Answer:

D. Positively charged particles

Explanation:

Negatively charged particles are attracted to positively charged particles and repelled against negatively charged particles

6 0
3 years ago
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