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3 years ago

Who EVER ANSWERS FIRST GETS 5 STARS AND BRAINLIEST

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

Part A. Riley and Louie each have $5,000 to invest. They both invest at a 2.5% simple interest rate.

Part B. Riley keeps her money invested for 7 years. How much interest will she earn?

Part C.After those 7 years how much will her investment be worth?

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What’s the answer to this

iren [92.7K]

Answer: (-2,4)

Step-by-step explanation:

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3 years ago

What is 3 to the 8th power times 3 to the 2nd power simplified and what law did you use?

hodyreva [135]

Answer:

$3^{10}$

Step-by-step explanation:

$3^{8}*3^{2}=3^{8+2}=3^{10}$

Using the multiplication/product law of exponents, you can add the exponents up.

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4 years ago

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Graph the system of equations: y=-x^2+3x-1 2y-1=x

Nana76 [90]

Y = -x² + 3x - 1
x = 2y - 1

x = 2(-x² + 3x - 1) - 1
x = 2(-x²) + 2(3x) + 2(-1) - 1
x = -2x² + 6x - 2 - 1
x = -2x² + 6x - 3
- x - x 
0 = -2x² + 5x - 3
x = -(5) +/- √((5)² - 4(-2)(-3))
 2(-2)
x = -5 +/- √(25 - 24)
 -4
x = -5 +/- √(1)
 -4
x = -5 +/- 1
 -4
x = -5 + 1 or x = -5 - 1
 -4 -4
x = -4 x = -6
 -4 -4
x = 1 x = 1.5

2y - 1 = x
2y - 1 = 1
 + 1 + 1
 2y = 2
 2 2
 y = 1
(x, y) = (1, 1)
or
2y - 1 = x
2y - 1 = 1.5
 + 1 + 1 
 2y = 2.5
 2 2
 y = 1.25
(x, y) = (1.5, 1.25)
The two solutions is equal to (1, 1) and (1.5, 1.25).

4 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

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3 years ago

The graph below shows the amount of time Misha spent outside over a 30-day period. How might the graph be considered misleading?

Sauron [17]

The y-interval shows exponential increase rather than linear increase.

4 0

3 years ago

Read 2 more answers