use sin^2(x) =1/2 * (1-cos2x)
cos 2x - use def cosx from table
f(x)=sin^2(0)
f'(x)=2*sin(x)*cos(x)
therefore f'(x)=sin(2x)
f''(x)=2cos(2x)
f'''(x)=-4sin(2x)=-4*f'(x)
<span>putting it into maclaurin's series</span>
<span>We get,</span>
<span> 0+0+ 2x^2/2! + 0...</span>
Check the picture below.
they're at a 3:1 ratio, thus, 3 times.
If I had to guess quickly I would say answer 1. Substitutes and follow/respect PEMDAS.
What is PEMDAS ? Order of operation: parenthesis, exponents, multiplication, division, addition, and subtraction (do them in order )
Answer is 1.538
Using (x1,y1)(x2,y2)
x1=0
Y1=2
X2=5.2
Y2=10
Answer:
Step-by-step explanation:
143
or
121
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does any of this help