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3 years ago

13

Lucy has $20 to spend at the store. She is already buying a shirt that costs $8. Which inequality can be used to find how much m

oney she has left to spend?

2 answers:

Anastasy [175]3 years ago

5 0

Answer: she will have 12 dollars left

Step-by-step explanation:

Troyanec [42]3 years ago

4 0

Answer:

X=20-8

Step-by-step explanation:

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1. What is the approximate area of a circle with a diameter of 20 inches?

ad-work [718]

Answer:

1. 100 $\pi$

2. 27 $cm^{3}$

3. 30

Step-by-step explanation:

Area = $\pi$ $r^{2}$

= $\pi$ x $10x^{2}$

= 100 $\pi$

Volume = l x w x h

= 3 x 3 x 3

= 27

7 0

3 years ago

2.199 rounded to the nearest whole number

steposvetlana [31]

Rounding 2.199. The tenths digit is 1, which is 4 or less, so you will round down. Re-write 2.199 without the decimal places: 2 . So 2.199 rounds to 2.

3 0

3 years ago

Solve each one variable equation.

uranmaximum [27]

Answer:

See below in bold.

Step-by-step explanation:

a. |x| = 6

x = 6, -6.

b. |x − 5| = 4

x - 5 = 4

x = 9.

x - 5 = -4

x = 1.

c. 2|x + 3| = −10

No solution because |x + 3| is an absolute value so is always positive.

8 0

3 years ago

Lina20 [59]

Answer:

$\textbf{The slope of the parallel line is given by $ 2 $}\\$

Step-by-step explanation:

$\textup{The slope of any two parallel lines are equal and they only differ in their $y- intercepts$. }\\\textup{Given $y = 2x + 4 $}\\\textup{This is comparable to $y = mx + c$, where $m$ is the slope of that line.}\\\textup{Therefore, the slope of the given line and any line parallel to it is $ 2$.}$

7 0

3 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.

</span> $x(2x+1)-2(2x+1)\ \textless \ 0$
<span>
Step 3: </span>Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. <span>Solve each of the 2 equations above:

</span> $x=- \frac{1}{2} ,2$
<span>
Step 5: </span>From the values of $x$ <span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: P</span><span>ick a test point for each interval

</span>For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.
<span>
For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this <span>interval.

For the interval </span> $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)</span>

4 0

4 years ago