Draw a diagram to illustrate the problem as shown below.
The area of triangle acb is
A₁ = (1/2)*20*h = 10h
The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h
The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8
Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.
Answer:
103
Step-by-step explanation:
Answer:
The answer is
![\sqrt[3]{ {x}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20)
Step-by-step explanation:

Since they have the same base and are dividing we can use the rules of indices
That's
subtract the exponents
So we have



Rewriting it in radical form
We have the final answer as
![\sqrt[3]{ {x}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20)
Hope this helps you