First, we obtain the gradient (slope) of the first parallel line

Recall that since both lines are parallel, we have that,

Thus

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)
Using
Answer:
look at the pictures
Step-by-step explanation:
40/100= 56/x
40x=100(56)
40x=5600
Divide both sides by 40 to get x alone.
X=140
Step-by-step explanation:
The formula for the volume of a sphere is V = 4/3 πr³.
So
Given
Volume (v) = 57ft³






![r = \sqrt[3]{13.6}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B13.6%7D%20)
Therefore r = 2.4 ft
I gave my answers by rounding off. so if you don't round off then it's answer is 2.3 ft
The characteristics of similar triangles, originally formulated by Euclid, are the building blocks of trigonometry. Euclid's theorems state if two angles of one triangle have the same measure as two angles of another triangle, then the two triangles are similar. Also, in similar triangles, angle measure and ratios of corresponding sides are preserved. Because all right triangles contain a 90° angle, all right triangles that contain another angle of equal measure must be similar. Therefore, the ratio of the corresponding sides of these triangles must be equal in value. These relationships lead to the trigonometric ratios. Lowercase Greek letters are usually used to name angle measures. It doesn't matter which letter is used, but two that are used quite often are alpha (α) and theta (θ).