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pashok25 [27]
3 years ago
9

What are the zeros of the function? what are their multiplicities? f(x)=x^4-4x^3+3x^2

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0
Since each term contains x, x= 0 is one answer Also as x^2 is a factor  it has duplicity 2.
Factoring:-

x^2 (x^2 - 4x + 3) = 0
x^2( x - 3)(x - 1) = 0

so x = 3 and x = 1 are also zeros


Answer:-   x = 0 (duplicity 2), x = 1 and x = 3.
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What is the length of BC?<br> A. 6 2/3 cm<br> B. 5cm<br> C. 4cm<br> D. 6cm
Sergio039 [100]

Thought I already answered this.  I must have forgotten to click "add your answer."

We have similar triangle trianges ABC ~ ADE so

BC:AB = DE:AD

BC:2  = 10 : (2+3) = 10:5 = 2:1

So BC=4 because 4:2 = 2:1

Choice C.

6 0
3 years ago
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zmey [24]
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2 years ago
Use the table to write a linear function that relates y to x.
blsea [12.9K]

Answer:

y = - \frac{2}{3} x

Step-by-step explanation:

the equation of a linear function in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 8, 2) and (x₂, y₂ ) = (1, - 4) ← 2 ordered pairs from the table

m = \frac{-4-2}{1-(-8)} = \frac{-6}{1+8} = \frac{-6}{9} = - \frac{2}{3}

the ordered pair (0, 0 ) indicates the line crosses through the origin, then

c = 0

y = - \frac{2}{3} x + 0 , that is

y = - \frac{2}{3} x ← equation of linear function

4 0
2 years ago
Find the equation of the ellipse with the following properties. The ellipse with foci at (0, 6) and (0, -6); y-intercepts (0, 8)
sesenic [268]
Hi, thank you for posting your question here at Brainly.

The general equation of a horizontal ellipse is

(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.

If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,

2b = 16
b = 8
b^2 = 64

The distance between the two foci is 2c. Thus,

2c = 12
c = 6
c^2 = 36

Then, a2 = 64 + 36 = 100. Substituting to the general equation:

x^2/100 + y^2/64 = 1
8 0
3 years ago
Mhanifa can you please help? This is due soon. Look at the picture attached. I will mark brainliest!
TEA [102]

Answer:

  • 84°
  • 125°

Step-by-step explanation:

<u>Sum of the interior angles of a regular polygon:</u>

  • S(n) = 180°(n - 2), where n- number of sides
<h3>Exercise 4</h3>

<u>Pentagon has sum of angles:</u>

  • S(5) = 180°(5 - 2) = 540°

<u>Sum the given angles and find x:</u>

  • x° + 122° + 100° + 90° + 144° = 540°
  • x° + 456° = 540°
  • x° = 540° - 456°
  • x° = 84°
<h3>Exercise 5</h3>

<u>Hexagon has sum of angles:</u>

  • S(6) = 180°(6 - 2) = 720°

<u>Sum the given angles and find x:</u>

  • x° + 110° + 160° + 105° + 105° + 115° = 720°
  • x° + 595° = 720°
  • x° = 720° - 595°
  • x° = 125°
5 0
3 years ago
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