How many solutions are there to the equation below?
2 answers:
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First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that
So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
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The answer has to be in y-intercept form. Which is y=mx+b and b can also be neg. y=mx-b. The m is your slope and b is your y-intercept. So A’s slope counting from 3 on the y axis to 1 on the x-axis which is down 2 over 1 so it will be -2/1. And your y intercept is 3. The equation is y=-2x+3. For B its the same thing but no graph. Remember that slope is RISE over RUN. So since the number is on the bottom of the line the rise is 4 and the run is 1. So in this case 10 is your y-intercept. Which means you equation is y=4x+10.
