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vampirchik [111]
3 years ago
14

Which interval contains the median number of hours worked?

Mathematics
2 answers:
Andrei [34K]3 years ago
6 0

Answer:

More information needed to answer please.

Artist 52 [7]3 years ago
3 0

Answer:

Starting with 0, add the frequencies in the table starting with the 1st row until you reach 8.

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The circumference of a circle is 7π in. Find its radius, in inches.
mezya [45]

Answer:

3.5 in

Step-by-step explanation:

Circumference = 2π(radius)

7π = 2π (radius)

7π/2π = radius

Pi in numerator and denominator cancel each other.

7/2  = radius

3.2 in = radius

4 0
3 years ago
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At a cafe, for every 8 hot dogs sold there are 11 hamburgers sold. What is the ratio of hot dogs sold to hamburgers sold?
Bezzdna [24]
I think 8:11 will be the answer
7 0
3 years ago
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Does this image have a vertical reflection, horizontal reflection, and rotation? I'll give brainiest!
ElenaW [278]

Answer:

Reflection with respect to the x axis

Step-by-step explanation:

Reflection with respect to the x avis, or horizontal reflection.

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3 years ago
Which is a not a triangle ?
leva [86]

Answer:

answer: d

Step-by-step explanation:

idek how to explain.

4 0
3 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
3 years ago
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