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GuDViN [60]
2 years ago
15

PLEASE HELP I USED ALL MY POINTS

Mathematics
2 answers:
Nady [450]2 years ago
5 0

Answer:

<em>Well, Your best answer will be is </em><em>B. Good Luck!</em>

Luba_88 [7]2 years ago
5 0

Answer:

yes, because it asks a question that can  be answered correctly?

Step-by-step explanation:

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Y=4 horizontal yes or no
Serga [27]

Answer:

yes

Step-by-step explanation:

The equation of a horizontal line parallel to the x-axis is

y = c

where c is the value of the y- coordinates the line passes through

y = 4 is a horizontal line passing through all points with a y- coordinate of 4

4 0
3 years ago
Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
Suppose n represents an even number for a simplified expression that represents the product of the next two even numbers
Digiron [165]
N+1 x n+2 = whatever that first part means
3 0
3 years ago
Read 2 more answers
5(n+1) = 2n + 20 can someone tell me the answer and explain
finlep [7]

Answer:

n=15

Step-by-step explanation:

5(n+1)=2n+20

U start by expanding the first term which will give you 5n+5

Then after that u collect like terms giving u

5n-2n=20-5

Finally u evaluate it giving u

n=15

8 0
3 years ago
Read 2 more answers
What is the square root of 56 in radical form
V125BC [204]
\sqrt{56}  \\  \\  \sqrt{7*8}  \\  \\  \sqrt{7*4*2}  \\  \\  \sqrt{7*2*2*2}  \\  \\ 2 \sqrt{7*2}  \\  \\ 2 \sqrt{14}
7 0
3 years ago
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