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4 years ago

20/10 as a mixed number

2 answers:

Klio2033 [76]4 years ago

8 0

First, decide how many times 10 can go into 20. 10 can "fit in" to 20 exactly 2 times. Since there is nothing left over, the "mixed number" is simply 2.
Another way to do this is to just divide the top by bottom, since it will divide evenly.
20/10 = 2.
Answer: 2
Hope that helps!!

IgorC [24]4 years ago

5 0

20/10 is not possible being a mixed number, simply because 10 can go into 20 evenly.

2 is the answer.

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Help me i did the first part tho lol

Kay [80]

Answer:

Step-by-step explanation:

3 0

3 years ago

The first week of January, there are 49 dogs and 28 cats in an animal shelter. Throughout the month the ratio of dogs to cats re

Alik [6]

Answer:

35 dogs

Step-by-step explanation:

We can simplify the ratio 49:28 by dividing by 7

The new ratio is 7:4 which is easier to work with.

It says there are 20 cats so we know that for every 4 cats there are 7 dogs

We simply multiply 20 by 7/4

20 x 7/4 = 35 so there are 35 dogs

5 0

3 years ago

Twice the difference of a number and 9 equals 8

ladessa [460]

Answer:

13 is the number.

Step-by-step explanation:

Given:

Twice the difference of a number and 9 equals 8.

Let the unknown number be 'x'.

Therefore, as per question:

The difference of 'x' and 9 = $x-9$

Twice the difference means 2 times the difference. So, we multiply 2 to the difference. Therefore,

$2(x-9)$

Now, the above expression is equal to 8. So, we equate the above expression to 8. This gives,

$2(x-9)=8$

Solving for 'x', we get:

Using distributive property of addition and distributing 2 inside the bracket. This gives,

$2\times x-2\times 9=8\\\\2x-18=8\\\\2x=8+18\\\\2x=26\\\\x=\frac{26}{2}=13$

Therefore, the unknown number is 13.

Now, we can verify our answer.

$2(13-9)=26-18=8$

Therefore, the answer is correct.

3 0

4 years ago

A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence

belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

$\mathbf{n = 5}$ --- the number of digits

$\mathbf{r = 3}$ ---- the number of actions

Each of the three actions can either be:

Pressing one button
Pressing a pair of buttons

The number of ways of pressing a button is:

$\mathbf{n_1 = ^5C_1}$

Apply combination formula

$\mathbf{n_1 = \frac{5!}{(5-1)!1!}}$

$\mathbf{n_1 = \frac{5!}{4!1!}}$

$\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}$

$\mathbf{n_1 = 5}$

The number of ways of pressing a pair is:

$\mathbf{n_2 = ^5C_2}$

Apply combination formula

$\mathbf{n_2 = \frac{5!}{(5-2)!2!}}$

$\mathbf{n_2 = \frac{5!}{3!2!}}$

$\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}$

$\mathbf{n_2 = 10}$

So, the number of ways of performing one action is:

$\mathbf{n =n_1 + n_2}$

$\mathbf{n =5 + 10}$

$\mathbf{n =15}$

For the three actions, the number of ways is:

$\mathbf{Action = n^3}$

$\mathbf{Action = 15^3}$

$\mathbf{Action = 3375}$

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

4 0

3 years ago

PLEASE HELP

saul85 [17]

Step-by-step explanation:

the answer is in the image above

6 0

3 years ago