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Leona [35]
3 years ago
9

The motion of any object can be broken down into it's component (parts of) vectors. true or false

Computers and Technology
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

The correct answer choice is true.

natta225 [31]3 years ago
7 0

It is a true fact that the motion of an object can be broken down into its components of vectors.  

True

<u>Explanation:</u>

The motion of an object is defined as the process of moving or being moved when considered under a particular frame of reference.

Any object undergoing the motion in any direction has components of vectors, one vector always acts in a direction of motion and the other vector acts perpendicular to  the direction of motion of the object.

Both the vectors are represented by sin and cos of angle.

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Answer:

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Given two objects represented by the tuples (22, 1, 42, 10) and (20, 0, 36, 8):
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Answer:

Given,

P = (22, 1, 42, 10)

Q = (20, 0, 36, 8)

a. Formula for Euclidean Distance :

distance = ((p1-q1)^2 + (p2-q2)^2 + ... + (pn-qn)^2)^(1/2)

Now,

distance = ( (22-20)^2 + (1-0)^2 + (42 - 36)^2 + (10-8)^2) ) ^(1/2)

=( (2)^2 + (1)^2 + (6)^2 + (2)^2 ) ) ^(1/2)

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b.Manhattan distance :

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2 years ago
If we are using an 4-character password that contains only lowercase English alphabetic characters (26 different characters), ho
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11,424,400 possible passwords

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9.11: Array Expander
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The Array Expander is an illustration of arrays and functions.

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<h3>The Array Expander program </h3>

The Array Expander program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This declares the Array Expander function

int* ArrayExpander(int *oldArr, int size){

   //This declares the new array

   int *newArr = new int[size * 2];

//This iteration sets values into the new array

   for (int i = 0; i < size * 2; i++) {

       if(i < size){

           *(newArr+i) = *(oldArr+i);

       }

       else{

           *(newArr+i) = 0;

       }

   }

//This returns a pointer to the new array

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//The main method begins here

int main(){

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   int N;    

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   int *ptr = ArrayExpander(initArr, N);

//This iteration prints the elements of the new array

   for (int i = 0; i < N*2; i++) {

       cout << ptr[i] << " ";

   }

   }

  return 0;

}

Read more abou C++ programs at:

brainly.com/question/27246607

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