Yes i would love to help the cause <span />
Ummmm the solution is ummm brb
Answer:
myInt=40
myFloat=4.8
Explanation:
First look at the function definition .It has two arguments intVal is passed by reference while floatVal is passed by value.So the changes done on the myInt variable will be reflected on the original argument because when a variable is passed by reference the the changes are reflected on the original argument but when a variable is passed by value the function created a duplicate copy of it and work on them so changes are not reflected on the original argument.So myInt will get doubled while myFloat will remain the same.
Hi,
Everything applies. It is impossible to predict based on the current data. All scenarios are possible with equal possibility.
Hope this helps.
r3t40
