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STALIN [3.7K]
3 years ago
10

a photographer's camera sits on a tripod that is 1.8 m above the ground. The base of the tripod is 44 m from the base of a tree.

The photographer's spot woodpecker in a tree at a 39 degree angle of elevation. To the nearest tenth of a meter, how high above the ground is the woodpecker? A.37.4m B.36.0m C.35.6m D.34.2m
Mathematics
1 answer:
MissTica3 years ago
5 0
I found 37.4 so letter A is the answer.
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Pls help if your good at math marking brainliest
LenaWriter [7]

Answer:

Step-by-step explanation:

6x-1=2x+5+4x-6

separate the variables in one side, numbers on the other side

6x-2x-4x=1+5-6

0=0

one solution

8 0
3 years ago
adult tickets to a movie cost $12 while children tickets cost $5. if a total of 500 tickets were sold and if $3550 was collected
svp [43]
The answer to the question

5 0
3 years ago
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
3 years ago
What is the remainder when x+ - 2x2 – 3x – 7 is divided by x + 2?
guapka [62]

x+-2*2-3x-7

x+4-3x-7

x+1.x-7

x.x-7

2x-7

4 0
3 years ago
32% of 1600 = 512
yaroslaw [1]

Answer:

  • 64%: 1024
  • 96%: 1536
  • 132%: 2112
  • 232%: 3712

Step-by-step explanation:

<u>64% of 1600</u>

  64% of 1600 = 2 × (32% of 1600) = 2×512

  64% of 1600 = 1024

<u>96% of 1600</u>

  96% of 1600 = 3 × (32% of 1600) = 3×512

  96% of 1600 = 1536

<u>132% of 1600</u>

  132% of 1600 = (100% of 1600) + (32% of 1600) = 1600 + 512

  132% of 1600 = 2112

<u>232% of 1600</u>

  232% of 1600 = (100% of 1600) + (132% of 1600) = 1600 +2112

  232% of 1600 = 3712

3 0
3 years ago
Read 2 more answers
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