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Leviafan [203]
3 years ago
9

5% of what number is 300?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

6000

Step-by-step explanation:

5% = 0.05.

0.05x = 300

<em>divide both sides of the equation by 0.05</em>

0.05x/0.05 = 300/0.05

x = 300/0.05

x = 6,000

svlad2 [7]3 years ago
3 0

Answer:

6000

Step-by-step explanation:

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What is the fully factored form of 32a^3 + 12a^2?
Klio2033 [76]

<u>Answer:</u>

4a^{2} (8a + 3)

<u>Step-by-step explanation:</u>

32a^3 + 12a^2

To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:

32a^3 + 12a^2

a^2 (32a + 12)

Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:

a^2 (32a + 12)

4a^2 (8a + 3)

So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).

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Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
4 years ago
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